expression let's say we have four times the quantity x minus y whatever X and Y are and then plus one and then I'm going to give you as a kind of like part of the problem that X is equal to negative 2 ...

Simplify \(\frac{3t + 6}{3t}\). The numerator of this fraction will factorise as there is a common factor of 3. This gives \(\frac{3(t + 2)}{3t}\). Now, there is clearly a common factor of 3 between ...