// height(’12’) = max(height(‘8′), height(’18’)) + 1 = 1 + 1 = 2 The idea is, if we take a closer look at the depth first traversal, we can notice that ...

You don't need to read input or print anything. Your task is to complete the function dupSub() which takes root of the tree as the only arguement and returns 1 if the binary tree contains a duplicate ...

An algorithm is given for constructing an alphabetic binary tree of minimum weighted path length (for short, an optimal alphabetic tree). The algorithm needs 4n 2 + 2n operations and 4n storage ...