Given two strings needle and haystack, return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Clarification: What should we return when needle is an ...
for(int i = 0; i <= haystack.length() - needle.length(); i ++) { 若j到达needle末位，则说明已经找到，返回i； 若i+j到达haystack末位 ...
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