How to find the antiderivative of $\\sqrt{25-x^2}$? How would I do it? Integration by substitution doesn't seem to work in this case.

$8^x + 16^x = 2 (25^x)$. The answer is clearly $0$, but myself and a couple others have not been able to find an elementary algebraic way to crack it, using properties of exponents, logs, etc. …

Mar 26, 2011 · There is a basic approach here, called "trigonometric substitution." This is something to use whenever you have an integral that contains a radical of any of the following …

Dec 9, 2020 · Using trigonometric substitution to integrate $\int\frac {x^3dx} {\sqrt {25-x^2}}$ Ask Question Asked 4 years, 11 months ago Modified 4 years, 11 months ago

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Jul 23, 2020 · Partial Fraction Decomposition of $\frac {1} {x^2 (x^2+25)}$ Ask Question Asked 5 years, 1 month ago Modified 5 years, 1 month ago

Jan 28, 2019 · This is what I did: I try to multiply by the conjugate. Its value I believe is technically the solution. $ (\sqrt {49-x^2} + \sqrt {25-x^2}) (\sqrt {49-x^2} - \sqrt ...

Dec 26, 2018 · The question is to find a vector equation for the tangent line to the curve of intersection of the cylinders $x^2+y^2=25$ and $y^2+z^2=20$ at the point $ (3,4,2)$.

Nov 8, 2018 · EDIT: A Late Addressing of OP's Actual Question: (No clue why I - or anyone outside the comments - never thought to actually do this years ago, but whatever.) OP's confusion lies …

Nov 2, 2014 · Volume = the integral of the area. I think that the area from bounded by x=$\sqrt (25-\sqrt (y^2)$ and the line x=3 is $\int_0^5 \sqrt (25-\sqrt (x^2)$ The upper bound of 5 comes …