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When comparing a double to zero in Java, direct equality checks (== 0.0) can be unreliable due to floating-point precision errors. Instead, use an epsilon-based comparison to account for tiny rounding differences.
Example:
public class CompareDouble {public static void main(String[] args) {double discriminant = 0.00000000000000001236;double EPSILON = 1e-9; // tolerance levelif (Math.abs(discriminant) < EPSILON) {System.out.println("Equal to zero");} else if (discriminant > 0) {System.out.println("Greater than zero");} else {System.out.println("Less than zero");}}}Copied!✕CopyThis approach ensures that values extremely close to zero are treated as zero, avoiding false negatives caused by floating-point representation issues.
Why not use == directly? Floating-point numbers like 0.1 cannot be represented exactly in binary, so calculations may produce results like 0.00000000000000001236 instead of 0.0. Direct equality fails in such cases.
Alternative Approaches:
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