1 DFómh 2012 · In Regex, . refers to any character, be it a number, an aplhabet character, or any other special character. * means zero or more times.

In case it is JS it indicates the start and end of the regex, like quotes for strings. stackoverflow.com/questions/15661969/…

14 MFómh 2010 · It indicates that the subpattern is a non-capture subpattern. That means whatever is matched in (?:\w+\s), even though it's enclosed by () it won't appear in the list of …

In regex in general, ^ is negation only at the beginning of a character class. Unless CMake is doing something really funky (to the point where calling their pattern matching language "regex" could …

17 Noll 2012 · Afaik, it depends on the regex flavor and the matching options whether a newline is considered as end-of-string.

59 That regex "\\s*,\\s*" means: \s* any number of whitespace characters a comma \s* any number of whitespace characters which will split on commas and consume any spaces either …

3 DFómh 2010 · Now, when the regex engine tries to match against aaaaaaaab, the .* will again consume the entire string. However, since the engine will have reached the end of the string …

2 Ean 1999 · Parentheses in regular expressions define groups, which is why you need to escape the parentheses to match the literal characters. So to modify the groups just remove all of the …

By putting ^ at the beginning of your regex and $ at the end, you ensure that no other characters are allowed before or after your regex. For example, the regex [0-9] matches the strings "9" as …

While writing this answer, I had to match exclusively on linebreaks instead of using the s-flag (dotall - dot matches linebreaks). The sites usually used to test regular expressions behave …