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  1. The pop operation in a linked list removes the head (first) node and returns its value. This is an O(1) operation since it only involves updating the head pointer.

    Example:

    # Node definition
    class Node:
    def __init__(self, data=None, next=None):
    self.data = data
    self.next = next

    # Helper to print the linked list
    def print_list(head):
    ptr = head
    while ptr:
    print(ptr.data, end=" -> ")
    ptr = ptr.next
    print("None")

    # Pop function: removes head and returns new head
    def pop(head):
    if head is None: # Underflow condition
    return None, None
    popped_value = head.data
    head = head.next # Move head to next node
    return popped_value, head

    # Example usage
    if __name__ == "__main__":
    # Create linked list: 1 -> 2 -> 3 -> 4 -> None
    head = None
    for i in reversed(range(1, 5)):
    head = Node(i, head)

    print("Original list:")
    print_list(head)

    value, head = pop(head)
    print(f"Popped value: {value}")

    print("After pop:")
    print_list(head)
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